Sahawatthanakit (1988) Co., Ltd.
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Sahawatthanakit (1988) Engineering Team10 min read

Power Factor Correction for Factories — Stop Paying MEA/PEA's 56.07 Baht/kVAR Penalty with a Capacitor Bank

How to fix low power factor in a Thai factory: why MEA/PEA charge when kVAR exceeds 61.97% of kW (PF < 0.85) at 56.07 baht/kVAR, how to size a capacitor bank (Qc = P(tanφ1−tanφ2)), fixed vs automatic APFC, the harmonics trap from VFDs that needs a detuned reactor per IEEE 519 / IEC 61921, and the ROI that is usually under one year.

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Capacitor bank panel for power factor correction in an industrial plant

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สรุป (TL;DR)

How to fix low power factor in a Thai factory: why MEA/PEA charge when kVAR exceeds 61.97% of kW (PF < 0.85) at 56.07 baht/kVAR, how to size a capacitor bank (Qc = P(tanφ1−tanφ2)), fixed vs automatic APFC, the harmonics trap from VFDs that needs a detuned reactor per IEEE 519 / IEC 61921, and the ROI that is usually under one year.

There's a line on a factory's electricity bill that many pay every month without noticing — the MEA/PEA Power Factor charge at 56.07 baht per kVAR for plants whose power factor is below 0.85. Some pay tens of thousands of baht a month, even though it can be fixed with a capacitor bank that pays for itself in under a year.

This article explains where that penalty comes from, how to size a capacitor bank, and the harmonics trap that — if missed — can destroy the capacitors early.


1. Why the utility penalises you — kW vs kVAR vs kVA

A factory load draws power in two parts:

  • kW (active power) — the part that does real work: turning motors, producing heat, light
  • kVAR (reactive power) — the part that builds the magnetic field in motors/transformers; it does no direct work but is needed

Together they make kVA (apparent power) via kVA² = kW² + kVAR², and power factor (PF) = kW / kVA = cos φ.

Induction motors, ballasts and transformers draw a lot of lagging kVAR, lowering PF. The utility must size cables and transformers for reactive current it "doesn't sell as energy," so it pushes that burden back as a penalty to encourage fixing it at the source.


2. Thailand's penalty rule — the numbers to know

Criterion Value
Penalty starts when kVAR (15-min max) exceeds 61.97% of kW max
Equivalent PF below ~0.85
Charge on the excess 56.07 baht / kVAR

Worked example: a plant peaks at 400 kW and 350 kVAR

  • Penalty-free ceiling = 400 × 0.6197 = 247.88 kVAR
  • Excess = 350 − 247.88 = 102.12 kVAR
  • Penalty = 102 × 56.07 ≈ 5,719 baht/month~68,600 baht/year paid for nothing

This is not an energy (kWh) charge — it is a penalty for low PF. Fix it once and it's gone permanently.


3. Fixing it with a capacitor bank — size and type

A capacitor supplies leading kVAR to cancel the load's lagging kVAR locally, so the kVAR through the meter drops.

Sizing: Qc = P × (tanφ1 − tanφ2)

  • P = active power (kW), φ1 = angle from present PF, φ2 = angle from target PF
  • Example: P = 400 kW, PF 0.75 → 0.95: Qc = 400 × (0.882 − 0.329) ≈ 221 kVAR

Choosing the type:

Type Best for
Fixed Constant loads — a transformer, or a single motor running continuously
Automatic (APFC) Variable loads — a panel switches capacitor steps to the real PF via a controller (most common in plants)

Beware over-correction: too much capacitance at light load makes PF leading (also bad, raising voltage). An APFC avoids this by switching steps automatically.


4. The key trap — harmonics from VFDs

Modern plants have VFDs, rectifiers, UPS and LED drivers = non-linear loads that create harmonic currents.

flowchart TD
  A[Measure PF + harmonics at the MDB] --> B{PF < 0.85?}
  B -->|No| Z[No fix needed — monitor]
  B -->|Yes| C[Compute Qc = P x tanphi1 - tanphi2]
  C --> D{Many VFD/non-linear loads?}
  D -->|Low harmonics| E[Standard capacitor bank]
  D -->|High harmonics| F[Detuned 7% reactor + capacitor]
  E --> G[Choose Fixed or APFC]
  F --> G
  G --> H[Install + re-measure, confirm PF > 0.85]

Installing a plain capacitor in a high-harmonic system can cause harmonic resonance between the capacitor and the system inductance → current surges → capacitors overheat, swell, blow fuses and fail early.

The fix: add a detuned reactor (a series reactor, typically 7%, tuned to ~189 Hz) ahead of the capacitor to shift the resonant frequency below the 5th harmonic (250 Hz), per IEEE 519 and IEC 61921. With very high harmonics, an active harmonic filter may be needed.

If your plant has many VFDs, see VFD sizing per IEC 61800 — the main harmonic source to account for when designing capacitors.


5. ROI + checklist before installing

ROI: the eliminated penalty (thousands–tens of thousands per month) against the bank + installation cost → usually under 1 year, plus freed transformer capacity as a bonus.

Before ordering, ask for:

  • 3–6 months of electricity bills to see the PF penalty line + real max kVAR/kW
  • Measure PF + harmonics (THD) at the MDB with a power-quality analyzer before designing
  • Compute Qc to a target PF of 0.92–0.95 (don't push to leading)
  • Choose APFC for variable loads + specify the number of steps
  • If many VFD/non-linear loads → specify a detuned 7% reactor + harmonic-rated (heavy-duty) capacitors
  • Capacitors + reactors meeting IEC 61921 / IEC 60831 + discharge resistors + protection
  • Re-measure PF after install, confirm it's above 0.85 and not leading at light load

Summary

The power factor penalty is money a factory pays for free every month when PF is below 0.85 — fix it with a correctly sized capacitor bank (Qc = P(tanφ1−tanφ2)), an APFC for variable loads, and don't forget the detuned reactor if you have VFDs/harmonics, or the capacitors fail early.

Start by reading the bill and measuring real PF; payback is usually under a year — one of the best-ROI energy investments in a plant.

Need a capacitor bank / APFC with detuned reactor designed and installed for a factory in Thailand — request a quote and our team can measure PF, size the kVAR and choose a harmonic-tolerant system.

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Frequently Asked Questions

1

How do MEA/PEA calculate the power factor penalty?

+
When the 15-minute maximum average reactive power demand (kVAR) in the billing period **exceeds 61.97% of the maximum active power demand (kW)** — equivalent to a power factor below about 0.85 — the excess is charged at **56.07 baht per kVAR**. Example: a 400 kW load with 350 kVAR exceeds by 350 − (400×0.6197) = 102 kVAR → penalty 102 × 56.07 ≈ 5,719 baht/month, paid every month for nothing in return.
2

How does a capacitor bank fix this?

+
Motors, transformers and ballasts draw lagging reactive power (kVAR). A capacitor supplies leading kVAR locally to cancel it, so the reactive current no longer has to flow from the utility → the kVAR at the meter drops → power factor rises above 0.85 → the penalty disappears. It is installed at the main distribution board or at large individual motors.
3

How do I size the kVAR to install?

+
Use `Qc = P × (tanφ1 − tanφ2)`, where P = active power (kW), φ1 = angle from the present PF, φ2 = angle from the target PF. Example: P=400 kW from PF 0.75 (tanφ1=0.882) to 0.95 (tanφ2=0.329): Qc = 400×(0.882−0.329) ≈ 221 kVAR. Choose an automatic (APFC) bank that switches steps with the real load so you don't over-correct.
4

Why must factories with VFDs be especially careful?

+
VFDs, rectifiers and UPS are non-linear loads that create harmonics. With a plain capacitor, harmonics can cause **resonance** with the capacitor, driving current up so the capacitor overheats, swells or fails. You need a **detuned reactor** (typically 7%, tuned ~189 Hz) in series with the capacitor to shift the resonant frequency away from the harmonics, per IEEE 519 / IEC 61921.
5

Is the capacitor bank ROI worth it?

+
Usually very much so — the eliminated PF penalty (thousands to tens of thousands of baht per month) versus the bank + installation cost means **payback is often under one year** for a plant penalised regularly. Beyond removing the penalty, it also lowers current in cables and the transformer, freeing capacity without upgrading the transformer.
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